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Monday, September 29, 2014

Taxonomy of Angiosperms


Taxonomy of Angiosperms

1.         The word taxonomy was coined by
            1) J.Hutchinson           2) Linnaeus                 3) A.P. de Candolle                4) Engler
2.         Taxonomy based on morphological characters alone is
            1) Omega taxonomy                                       2) Numerical taxonomy
            3) Phylogenetic taxonomy                              4) Alpha taxonomy
3.         Assertion(A): Phylogenetic system of classification of plants was proposed in a book Genera plantarum.
             Reason(R):Post-darwinian classifications are phylogenetic classifications.
            1)  A and R are true and R explains A           2) A and R are true but R does not explains A         
3) A is true but R is false                                4) A is false but R is true
4.         Taxonomy includes ……….. basic components
            1) Five                         2) Two                         3) Three                       4) Four
5.         Numerical taxonomy is different from artificial system of classifications in giving
            1) Importance to natural relationships                        2) Importance to evolutionary trends
            3) Importance to all characters                                    4) Importance to serological tests
6.         Assertion (A): Artificial systems are not acceptable due to equal weightage to vegetative and floral characters
            Reason (R): Vegetative characters are not stable and more easily affected by environment
            1)  A and R are true and R explains A           2) A and R are true but R does not explains A         
3) A is true but R is false                                4) A is false but R is true
7.           Match the following
            1) Species plantarum                         A) Hutchinson
            2) Genera plantarum                                    B) Linnaeus
            3) Historia plantaum                                     C) Engler & Prantl  
4) Die narurlichen planzen familien            D) Bentham & Hooker
                                                                                    E) Theophrastus       
            1)1-B,2-D,3-E,4-C                  2) 1)1-B,2-D,3-A,4-C                                                            
            3) 1)1-D,2-B,3-E,4-C              4) 1)1-E,2-D,3-C,4-B
8.         APG system is an example for
            1) Oldest phylogenetic classification          2) Latest natural system of classification
            3) Latest phylogenetic classification           4) Latest alpha taxonomy
9.         Identify the wrong pair in Bentham and Hooker’s system
              1) Classes-3               2) Series-6               3) Natural orders-202     4) Monocot families -34
10.       ,,,,,,,.
            Which of the following is not true with regard to the above floral  formula of mustard?
            1) Bracts & Bracteoles are absent               2) Flower is actinomorphic                                                         3) Flower is incomplete               4) Bicarpellary syncarpus superior ovary
11.       Mother axis in a floral diagram represents
            1) Anterior side           2) Right side            3) Left side                     4) Posterior side
12.       ,,  the number of floral leaves in it is
            1) 14                            2) 10                            3) 16                            4) 18
13.       the number of whorls showing cohesion is/are
            1) 1                              2) 2                              3) 3                              4) 4
14.  Series having same number of cohorts in gamopetalae of Bentham and Hooker system
       I) Disciflorae and Bicarpellatae                         II) Calyciflorae and Inferae
       III) Heteromerae and Thalamiflorae                 IV) Heteromerae and Inferae
       1) I & IV                         2) II & III                     3) only IV                     4) III & IV
15.  Mustard flower is
       1) Actinomorphic, pentamerous, bisexual             2) Zygomorphic, tetramerous, bisexual
       3) Ebracteate, ebracteolate, pentamerous             4) Ebracteate, tetramerous, actinomorphic and bisexual
16.  Plant systematics is the study of
       I) Diversity of plants      II) History of plants    III) Evolutionary relationships among the plants
       1) I & II                           2) II & III                     3) only III                     4) I, II, III
17.  Assertion (A): Numerical taxonomy uses mathematical methods to evaluate observable differences and similarities between taxonomic groups
       Reason (R): Information from other branches like cytology, palynology, phytochemistry but not morphological characters forms criteria in omega taxonomy
       1) Both ‘A’ and ‘R’ are true and ‘R’ is correct explanation to ‘A’.
       2) Both ‘A’ and ‘R’ are true but ‘R’ is not correct explanation to ‘A’
       3) ‘A’ is true but ‘R’ is false                                 4) ‘A’ is false but ‘R’ is true
18.  The symbols ,  in it’s floral formula indicates that the flower belongs to
       1) Brassicaceae                2) Solanaceae                3) Fabaceae                   4) Liliaceae
19.  The book ‘Families of flowering plants’ contains
       1) Phylogenetic classification of Engler and Prantle
       2) Natural classification of Bentham and Hooker
       3) Sexual system of Linnaeus                               4) Phylogenetic classification of Hutchinson
20.  Based on the number of cohorts arrange the following series of Bentham and Hooker classification in ascending order
       A) Bicarpellatae             B) Thalamiflorae         C) Calyciflorae            D) Heteromerae
       1) B-C-A-D                     2) C-D-B-A                  3) D-A-C-B                  4) A-B-C-D
21.  This character can be represented only in floral diagram
       1) Fusion of floral parts                                        2) Position of gynoecium 
       3) Adhesion of floral parts                                    4) Aestivation of perianth
22.  In Bentham & Hooker’s classification series calyciflorae is
       1) After thalamiflorae and before disciflorae       2) After disciflorae and before inferae
       3) After inferae and before bicarpellatae              4) After heteromerae and before bicarpellatae
23.  How many series are found in the sub class of class dicotyledonae in which cohorts are not created in Bentham and Hooker’s classification?
       1) 7                                  2) 8                                3) 6                                4) 4
24.  Which of the following is not found in a flower of Brassica
       1) Radial symmetry                                               2) Bicarpellary syncarpous gynoecium
       3) Polypetalous corolla                                          4) Epipetalous stamens
25.      How many stamens lie on the antero-posterior line in the flower of Allium cepa?
           1) 2                                2) 3                                3) 4                                4) 6             
26.    Which of the following characters of flowers cannot be represented in floral formula ?
          A. Sexuality of the flower                             B. Symmetry of the flower
          C. Number of floral organs in a whorl      D. Number of locules in the ovary
          E. Cohesion of sepals                                     F. Type of aestivation
          1) A, B, C                     2) D and F                   3) D alone                   4) A, C, E & F
27.      Members of Solanaceae differ with members of Liliaceae by having
            1)Axile placentation                                                2) Hypogynous flowers
            3) Pentamerous flowers                              4) Superior ovary


28.      Match the following :
            List – I                                                           List – II
A)                Meadow saffron                              I) Dracaena aungustifolia
B)                Sarasaparilla                                   II) Gloriosa superba
C)                Spanish dagger                                III) Colchicum autumnale
D)                Red dragon                                       IV) Smilax zeylanica
                                                                                     V) Yucca gloriosa
The correct match is
                        A         B         C         D                                 A         B         C         D
            1)        I           IV        III        V                     2)        III        IV        I           V
            3)        III        IV        V         I                       4)        V         IV        II          III
29.      Study the following characters
             Bicarpellary ovary , syncarpous ovary, bilocular ovary, Superior ovary , unequal lengthed stamens, polypetalous corolla, Six stamens, dry fruit, ovales attached to false septum, Tetramerous flower, Ebracteate flower, bisexual flower, hypogynous flowers
          How many characters  from the above list observed in the taxon “Brassica
            1) 10                                       2) 6                                         3) 12                           4) 13
30.      Liliaceae members with unisexual flowers are
            1)Asparagus, Allium                                                2)Smilax, Gloriosa              
3)Ruscus, Smilax                                                     4)Lilium, Allium
31.      Floral formula    ,   is that of
            1) Kamanchi             2)Onion                     3)Garden pea                        4) Garlic
32.      The ratio of tepals, stamens and carpels of a flower in Allium cepa is
            1) 1 : 2 : 2                  2)2 : 2: 1                    3)1 : 1 : 1                   4) 1 : 1 : 2
33.       Match the following
             List I                                                          List II
a)     Fenu greek                                             I) Medicine
b)     Sunhemp                                                 II) Edible oil
c)     Kanuga                                                    III) Timber
d)     Soya bean                                               IV) Leafy vegetable
                                                                                    V) Fodder plant
            The correct match is
            A         B         C         D                                A           B         C         D
1)        IV        V         I           II                      2)       IV         V         II          I
3)        IV        I           II          III                    4)       IV         III        II          V
34.    A subclass without cohorts
         1)Monocotyledonae      2)Monochlamydeae                              3)Gymnospermae        4)All the above
35.    Arrange the following in ascending order with reference to Bentham and Hooker classification
         I – Total number of cohorts                 II – Natural orders in moncotyledonae
        III – Cohorts in polypetalae                 IV – Total number of series            
         V – Series in Dicotyledonae
         1) V,III,IV,I,II             2)II,I,IV,III,V  3)V,IV,I,II,III            4)III,V,IV,I,II
36.     Floral diagram indicates
          I) Aestivation of perianth parts                             II) Number of floral parts in each whorl
          III) Cohesion and adhesion of floral parts           IV) Sexuality of the flower
          1) I & II only                 2) I, III & IV only             3) I & IV only                  4) I, II, III & IV
37.     Common character between Fabaceae and Solanaceae is                                                                   1) Connation of stamens  2) Union of carpels              3) Union of sepals            4) Aestivation of petals


38.     Identify the plant which shows following characters                                                                      
          I) Bicollateral vascular bundles                       II) Carpels are tilted by an angle of 45°                
          III) Dry dehiscent fruit                                     IV) Solitary terminal inflorescences                      
          1) Solanum                    2) Datura                       3) Atropa                           4) Nicotiana
39.     The book "Die naturlichen planzen familien" was written by                                           
          1) Bentham & Hooker 2) Engler & Prantl         3) Goldberg & Linnaeus    4) A.P. de candolle
40.     Plant from which chemical mutagen (Colchicine) is extracted shows the following stem modification  

          1) Corm                         2) Rhizome                   3) Bulb                               4) Cladode 

Sexual Reproduction in flowering plants

Sexual Reproduction in flowering plants

1.       Match the following.
          List-I                       List-II
          A)  Floriculture      I)  Pollen Fossilization
          B)  Embryology      II) The growing of ornamental flower bearing plants
          C)  Pollen robbery III) Preservation of viable pollen
          D)  Pollen Bank      IV) The study of events of fertilization
                                           V)  Consumption of pollen of flowers by insects without helping in pollination
          The correct match is
                A              B                C                D                        A              B                 C                D
          1)                    II               IV               V                   I                    2)  II            IV               V            III
          3)                    II               III               IV                 V                   4)  II            I                  IV           III
2.       The processes of microsporogenesis, megasporogenesis and embryogenesis occur respectively in
          1)  Anther, ovule, stigma                                           2)  Anther, style, ovule
          3)  Ovule, ovary, embryosac                                      4)  Anther, ovule, embryosac
3.       The wrong match regarding the morphology of following structures is
          1)  Stamen – Microsporophyll                                   2)  Carpel – Megasporophyll
          3)  Nucellus – Microsporangium                               4)  Flower – Modified shoot
4.       Choose the correct statement from following.
          1)  The pollensacs are transversely arranged in the anther
          2)  Tapetum is the female sporophytic nutritive tissue
          3)  Pollengrains are meiospores while pollen mother cells are meiocytes
          4)  The radial walls of endothecium have thickenings for hygroscopic activity
5.       The ratio between the number of male gametes produced by a male gametophyte and female gametes by a female gametophyte is
          1)  2 : 1                             2)  1 : 2                             3)  1 : 1                             4)  3 : 7
6.       The vegetative cell and generative cell of male gametophyte of angiosperms differ in their
          A)  Cell size                      B)  Cell shape                  C)  Shape of nucleus      D)  Size of nucleus
          1)  A, B only                     2)  C, D only                    3)  A, B, C only                4)  A, B, C, D
7.       Match the following.
          List-I                                                                         List-II
          A)  Pollengrain                                                         I)  Mother cell of male gametes
          B)  Megaspore                                                          II) Mother cell of male gametophyte
          C)  Central cell of embryosac                                 III) Sister cell of male gamete
          D)  Generative cell                                                   IV) Mother cell of female gametophyte
                                                                                             V)  Mother cell of endosperm
          The correct match is
                A              B                C                D                        A              B                 C                D
          1)  II               IV              V                I                    2)  II             IV               V                III
          3)  II               III              IV               V                   4)  II             I                  IV               III
8.       The pentacarpellary, syncarpous gynoecium with free stigmas and multicarpellary syncarpous gynoecium without style are respectively found in
          1)  Hibiscus and Annona  2)  Papaver and Michelia 3)  Hibiscus and Papaver  4)  Annona and Michelia
9.       Assertion (A) : The ovule is called megasporangium.
          Reason    (R) : The ovule contains nucellus, in which a megaspore mother cell is differentiated from the chalagal side.
          1)  A and R are true and R is the correct explanation of A.
          2)  A and R are true and R is not the correct explanation of A.
          3)  A is true, R is false.                                              4)  A is false, R is true.

10.     Wrong match of the following is
          1)  Loranthus – Anatropous ovule with single integument
          2)  Dolichos – Compylotropous ovule with two integuments
          3)  Polygonum – Ovule with micropyle, chalaza and funiculus on the same vertical line
          4)  Helianthus – Ovule with 1800 of curvature and single integument
11.     The typical embryosac of angiosperm is
          I)  Monosporic with genetically dissimilar 8 haploid nuclei
          II) Monosporic haploid, with six monokaryotic cells and one dikaryotic cell
          III) Monosporic with egg apparatus of 3 cells, antipodals of 3 cells and one central cell
          IV) Monosporic, develops from a single megaspore with 7 free nuclear divisions
          1)  All are correct except I                                         2)  All are correct except II
          3)  All are correct except III                                      4)  All are correct except IV
12.     The functional megaspore becomes embryosac in angiosperms due to cellularization after free-nuclear divisions with arrangement of cells as
          1)  Central cell in between chalazal egg apparatus and micropylar antipodals
          2)  Central cell in between micropylar egg apparatus and chalazal antipodals
          3)  Egg apparatus and central cell of chalazal side and antipodals of micropylar side
          4)  Egg apparatus of micropylar side and peripheral antipodals and central cell
13.     The growth of pollen tube is directed into the embryosac through synergid by
          1)  Antipodals                                                            2)  Polar nuclei
          3)  Filiform apparatus of egg cell                              4)  Filiform apparatus of synergid
14.     The total number of genomes in all the cells of angiospermic typical embryosac together is
          1)  7                                  2)  3                                  3)  5                                  4)  8
15.      Assertion (A) : Pollination is compulsory for fertilization in spermatophytic plants.
           Reason    (R) : The type of fertilization in all spermatophytes is double fertilization
         1)  A and R are true and R is the correct explanation of A.
         2)  A and R are true and R is not the correct explanation of A.
         3)  A is true, R is false.                                          4)  A is false, R is true.
16.      Arrange the following in correct ascending order based on their number
           I) Types of pollination in angiosperms            II) Types of flowers in commelina
           III) Types of cells in typical embryosac of angiosperms
           IV)  The embryosacs formed in a ovule
           1) IV, II, I, III             2) IV, I, II, III               3) III, I, II, IV                     4) IV, III, I, II
17.      Which of the following is not a character of anemorphilous flowers.
           1) Non sticky light pollengrains                          2) Feathery stigma              
           3) Ovary with single ovule                                  4) Unexposed stamens
18.      Match the following
           List – I                         List – II
           A) Maize                      I) Hypohydrophilous fresh water plant
           B) Yucca                     II) Long silky styles
           C) Commelina            III) Marine plant with long pollen grains
           D) Zostera                   IV) Mutual association with pollinator
                                                V) Both chasmogameous and cleistogamous flowers
           The correct match is
                     A              B               C               D                                  A               B              C              D
           1)      II              IV             V               I                      2)           II               IV             V              III
           3)      II              III             IV             V                     4)           II               I                IV             III
19.      Pickout the correct statement from following
           1) Diclinous flowers may be autogamous (or) allogamous
           2) Majority of hydrophytes have entomophilous flowers
           3) Chasmogamous flowers are always allogamous
           4) Cleistogamous flowers may be autogamous (or) Geitonogamous
20.      Wrong match with reference to type of pollination and type of agent
           1) Therophily – squirrels                                     2) Ophiophily – snakes
           3) chiropterophily – snails                                   4) Ornithophily – Birds
21.      Arrange the following steps of artificial hybridization in correct sequence of their performance from beginning
           A) Emasculation         B) Selection of parents                                              C) Bagging    
           D) Transfer of desired pollen                                                                        E) Rebagging
           1) B, A, C, D, E           2) B, A, E, C, D             3) E, D, C, A, B                   4) B, A, D, C, E
22.      Due to bursting of pollen tube after entering the embryosac, the male gametes are first released into the
           1) Central cell                                                      2) Egg cell                           
           3) Cytoplasm of synergid                                   4) Space between egg cell and synergid
23.      When tetraploid (4x) female plant is crossed with hexaploid (6x) male plant, with basic set number of chromosomes is 9, then the number of nuclei, the number of genomes and the number of chromosomes respectively participate in double fertilization respectively are
           1) 5, 12, 108                 2) 5, 13, 117                   3) 12, 12, 108                       4) 5, 5, 45
24.      Assertion (A) : The second nuclear fusion of double fertilization is called triple fusion
           Reason     (R) : The second fertilization of double fertilization involves the fusion the two male gametic nuclei and one female gametic nucleus
         1)  A and R are true and R is the correct explanation of A.
         2)  A and R are true and R is not the correct explanation of A.
         3)  A is true, R is false.                                          4)  A is false, R is true.
25.      Which of the following plant contains both nuclear endosperm and cellular endosperm.
           1) Bean                         2) Castor                        3) Coconut                           4) Wheat
26.      Find the ratio between the following structures with endosperm and without endosperm.
           A) Castor seed            B) Ground nut seed     C) Coconut fruit
           D) Bean seed               E) Maize seed                F)Pea seed
           1) 1 : 1                          2) 5 : 1                            3) 1 : 2                                  4) 2 : 1
27.      The structures of monocot embryo that are not found in dicot embryo are
           A) Coleoptile               B) coleorhiza                 C) endosperm                     D) Perisperm
           1) A, B                         2) C, D                           3) A, B, C                            4) A, B, C, D
28.    Ploidy of food storing tissue in the seeds of Ricinus and Pea respectively
          1) 2 n & 2n                   2) 2 n & 3n                3) 3n & 2n                 4) 3n &3n
29.    What is the correct arrangement of different stages of embryo?
          A. Globular                 B. Proembryo          C. Heart shaped      D. Mature embryo
          1) ABCD                      2) BCAD                    3) BACD                    4) DBAC
30.    Epiblast refers to a flap like outgrowth  of
          1) Epicotyle                 2) Hypocotyle           3) Coleoptile             4) Coleorhiza
31.      Given figure represents longitudinal section of a monocotyledonous embryo .
            Identify the parts labeled as A , B , C and D from the (i – vii) and select the
                                              
             i) Scutellum             ii) Coleoptile              iii) Shoot apex           iv)  Plumule
             v) Radicle                vi) Root cap               vii) Coleorhiza
             A   B   C   D                   A   B   C   D                A   B   C   D                 A   B   C   D
          1) i  vi   vii   ii             2) ii   vii   v   iii           3) ii   vii  iv    i            4)  iii  vii  vi  i
32.    Endosperm of which fruit is the main food of human beings?
          1) Caryopsis                2) Berry                     3) Cypsela                 4) Pome

33.    Diploid nutritive tissue in the seeds of black pepper and beet root is
          1) Endosperm              2) Perisperm              3) Male gametophytic tissue          4) Embryo
34.    Find the incorrect statement
          1) Size of orchid seed is 85 micrometers
          2) Weight of orchid seed is 0.81 micrograms
          3) Length of Seed of Lodecia is 30 cm       
          4) Circumference of seed of Lodoecia is 18 cm
35.    Which of the following is not related to seeds of  angiosperms
          1) the nourishment of young seedlings            2) help in dispersal to far off places
          3) Generate new genetic recombinations
          4) Dormancy and hydration are crucial for storage of seeds
36.    Find a disadvantage of hybrid seeds
          1) More yield                                                              2) More genetic recombinations
          3) More vigour and growth                                       4) Have to be produced every year
37.    Seed of which plant with long viability was discovered in archeological excavation at king Herod’s palace near the Dead Sea?
          1) Phoenix dactylifera                                                           2) Ficus elastica
          3) Lupinus arcticus                                                    4) Citrus sinensis
38.    Find the true match
            Column – I    (Event)                                  Column – II (Formation of )
          I. Apomixis                                                     A. asexual embryos from nucellus
          II. Parthenogenesis                                       B. fruit from ovary without fertilisation
          III. Parthenocarpy                                        C. embryo from egg cell without fertilization
          IV. Polyembryony                                         D. Seeds from ovule without fertilization
                        I          II         III       IV                   I          II         III       IV
          1)           D        C         B         A         2)        C         D         A         B
          3)           A         B         C         D         4)        D         C         A         B
39.    Apomictic seeds are found in
          1) All flowering plants                                               2) Allium and Cycas                       
          3) All species of Asteraceae and Grasses               4) Some species of Asteraceae and Grasses
40.     Select the correct statements from the following
I) Seeds of orange contain many embryos of different sizes and shapes
II) Apomixis is a form of asexual reproduction that mimics sexual reproduction
III) Double coconut is a worlds largest plant that gives rise to largest seeds
IV) Dehydration and dormancy of mature seeds are crucial for storage of seeds for future use

1)II&III                            2)I II & IV                        3)II & IV                            4)I & IV