Sexual
Reproduction in flowering plants
1. Match the following.
List-I List-II
A) Floriculture I) Pollen Fossilization
B) Embryology II)
The growing of ornamental flower bearing plants
C) Pollen robbery III) Preservation of viable pollen
D) Pollen Bank IV)
The study of events of fertilization
V) Consumption of pollen of flowers by insects
without helping in pollination
The correct match is
A B C D A B C D
1)
II IV V I 2) II IV V III
3)
II III IV V 4) II I IV III
2. The processes of microsporogenesis,
megasporogenesis and embryogenesis occur respectively in
1) Anther, ovule, stigma 2) Anther, style, ovule
3) Ovule, ovary,
embryosac 4) Anther, ovule, embryosac
3. The wrong match regarding the morphology
of following structures is
1) Stamen – Microsporophyll 2) Carpel – Megasporophyll
3) Nucellus –
Microsporangium 4) Flower – Modified shoot
4. Choose the correct statement from
following.
1) The pollensacs are transversely arranged in
the anther
2) Tapetum is the
female sporophytic nutritive tissue
3)
Pollengrains are meiospores while pollen mother cells are meiocytes
4) The radial walls
of endothecium have thickenings for hygroscopic activity
5. The ratio between the number of male
gametes produced by a male gametophyte and female gametes by a female
gametophyte is
1) 2 : 1 2) 1 : 2 3) 1 : 1 4) 3 : 7
6. The vegetative cell and generative cell
of male gametophyte of angiosperms differ in their
A)
Cell size B) Cell shape C) Shape of nucleus D) Size of nucleus
1) A, B only 2) C, D only 3) A, B, C only 4) A, B, C, D
7. Match the following.
List-I List-II
A) Pollengrain I) Mother cell of male gametes
B) Megaspore II)
Mother cell of male gametophyte
C) Central cell of embryosac III) Sister
cell of male gamete
D) Generative cell IV) Mother cell of
female gametophyte
V) Mother cell of endosperm
The correct match is
A B C D A B C D
1) II IV V I 2) II IV V III
3)
II III IV V 4) II I IV III
8. The
pentacarpellary, syncarpous gynoecium with free stigmas and multicarpellary
syncarpous gynoecium without style are respectively found in
1) Hibiscus and Annona 2) Papaver and Michelia 3)
Hibiscus and Papaver 4) Annona and Michelia
9. Assertion (A) : The ovule is
called megasporangium.
Reason (R) : The ovule contains nucellus, in
which a megaspore mother cell is differentiated from the chalagal side.
1)
A and R are true and R is the correct explanation of A.
2)
A and R are true and R is not the correct explanation of A.
3) A is true, R is false. 4) A is false, R is true.
10. Wrong match of the following is
1) Loranthus – Anatropous ovule with single
integument
2) Dolichos – Compylotropous ovule with two integuments
3) Polygonum – Ovule with micropyle, chalaza and
funiculus on the same vertical line
4) Helianthus – Ovule with 1800 of
curvature and single integument
11. The typical embryosac of angiosperm is
I)
Monosporic with genetically dissimilar 8 haploid nuclei
II) Monosporic haploid, with six
monokaryotic cells and one dikaryotic cell
III) Monosporic with egg apparatus of
3 cells, antipodals of 3 cells and one central cell
IV) Monosporic, develops from a single
megaspore with 7 free nuclear divisions
1) All are correct except I 2) All are correct except II
3) All are correct except III 4) All are correct except IV
12. The functional megaspore becomes embryosac
in angiosperms due to cellularization after free-nuclear divisions with arrangement
of cells as
1) Central cell in between chalazal egg
apparatus and micropylar antipodals
2) Central cell in between micropylar egg
apparatus and chalazal antipodals
3) Egg apparatus and central cell of chalazal
side and antipodals of micropylar side
4) Egg apparatus of micropylar side and
peripheral antipodals and central cell
13. The growth of pollen tube is directed into
the embryosac through synergid by
1) Antipodals 2) Polar nuclei
3) Filiform apparatus of egg cell 4) Filiform apparatus of synergid
14. The total number of genomes in all the
cells of angiospermic typical embryosac together is
1) 7 2) 3 3) 5 4) 8
15. Assertion (A) : Pollination is compulsory for fertilization in
spermatophytic plants.
Reason (R) : The
type of fertilization in all spermatophytes is double fertilization
1)
A and R are true and R is the correct explanation of A.
2) A and R are true
and R is not the correct explanation of A.
3) A is true,
R is false. 4) A is false, R is true.
16. Arrange the following in correct ascending order based on their
number
I) Types of pollination in angiosperms II) Types of flowers in commelina
III) Types of cells in typical embryosac of angiosperms
IV) The embryosacs
formed in a ovule
1) IV, II, I, III 2) IV, I, II, III 3) III, I, II, IV 4) IV, III, I, II
17. Which of the following is not a character of anemorphilous
flowers.
1) Non sticky light pollengrains 2) Feathery stigma
3) Ovary with single ovule 4)
Unexposed stamens
18. Match the following
List – I List
– II
A) Maize I)
Hypohydrophilous fresh water plant
B) Yucca II)
Long silky styles
C) Commelina III)
Marine plant with long pollen grains
D) Zostera IV)
Mutual association with pollinator
V) Both chasmogameous
and cleistogamous flowers
The correct match is
A B C D A B C D
1) II IV V I 2) II IV V III
3)
II III IV V 4) II I IV III
19. Pickout the correct statement from following
1) Diclinous flowers may be
autogamous (or) allogamous
2) Majority of hydrophytes
have entomophilous flowers
3) Chasmogamous flowers are always
allogamous
4) Cleistogamous flowers may be
autogamous (or) Geitonogamous
20. Wrong match with reference to type of pollination and type of
agent
1) Therophily – squirrels 2)
Ophiophily – snakes
3) chiropterophily – snails 4)
Ornithophily – Birds
21. Arrange the following steps of artificial hybridization in
correct sequence of their performance from beginning
A) Emasculation B)
Selection of parents C)
Bagging
D) Transfer of desired pollen E)
Rebagging
1) B, A, C, D, E 2) B, A, E, C, D 3) E, D, C, A, B 4) B, A, D, C, E
22. Due to bursting of pollen tube after entering the embryosac,
the male gametes are first released into the
1) Central cell 2)
Egg cell
3) Cytoplasm of synergid 4) Space
between egg cell and synergid
23. When tetraploid (4x) female plant is crossed with hexaploid
(6x) male plant, with basic set number of chromosomes is 9, then the number of
nuclei, the number of genomes and the number of chromosomes respectively
participate in double fertilization respectively are
1) 5, 12, 108 2) 5, 13, 117 3) 12, 12, 108 4) 5, 5, 45
24. Assertion (A) : The second nuclear fusion of double
fertilization is called triple fusion
Reason (R) : The
second fertilization of double fertilization involves the fusion the two male
gametic nuclei and one female gametic nucleus
1)
A and R are true and R is the correct explanation of A.
2) A and R are true
and R is not the correct explanation of A.
3) A is true,
R is false. 4) A is false, R is true.
25. Which of the following plant contains both nuclear endosperm
and cellular endosperm.
1) Bean 2) Castor 3)
Coconut 4) Wheat
26. Find the ratio between the following structures with endosperm
and without endosperm.
A) Castor seed B)
Ground nut seed C) Coconut fruit
D) Bean seed E)
Maize seed F)Pea seed
1) 1 : 1 2) 5 : 1 3) 1 : 2 4) 2 : 1
27. The structures of monocot embryo that are not found in dicot
embryo are
A) Coleoptile B)
coleorhiza C) endosperm D) Perisperm
1) A, B 2) C, D 3)
A, B, C 4) A,
B, C, D
28. Ploidy of food storing tissue in the seeds
of Ricinus and Pea respectively
1) 2 n & 2n 2)
2 n & 3n 3) 3n
& 2n 4) 3n &3n
29. What is the correct arrangement of different
stages of embryo?
A. Globular B. Proembryo C.
Heart shaped D. Mature embryo
1)
ABCD 2) BCAD 3) BACD 4) DBAC
30. Epiblast refers to a flap like
outgrowth of
1)
Epicotyle 2) Hypocotyle 3) Coleoptile 4) Coleorhiza
31. Given figure represents longitudinal section
of a monocotyledonous embryo .
Identify the parts labeled as A , B , C and D from the (i – vii) and
select the
i) Scutellum ii)
Coleoptile iii) Shoot apex iv)
Plumule
v) Radicle vi) Root
cap vii) Coleorhiza
A B C D A
B C D A
B C D A
B C D
1)
i vi
vii ii 2) ii vii v
iii 3) ii vii
iv i 4) iii vii
vi i
32. Endosperm of which fruit is the main food of
human beings?
1)
Caryopsis 2) Berry
33. Diploid
nutritive tissue in the seeds of black pepper and beet root is
1) Endosperm 2) Perisperm 3)
Male gametophytic tissue 4)
Embryo
34. Find
the incorrect statement
1) Size of orchid seed is 85
micrometers
2) Weight of orchid seed is 0.81
micrograms
3) Length of Seed of Lodecia is 30 cm
4) Circumference of seed of Lodoecia
is 18 cm
35. Which
of the following is not related to seeds of
angiosperms
1) the nourishment of young seedlings
2) help in dispersal to far off places
3) Generate new genetic recombinations
4) Dormancy and hydration are
crucial for storage of seeds
36. Find
a disadvantage of hybrid seeds
1) More yield 2) More
genetic recombinations
3) More vigour and growth 4)
Have to be produced every year
37. Seed
of which plant with long viability was discovered in archeological excavation at
king Herod’s palace near the Dead Sea ?
1) Phoenix
3) Lupinus arcticus 4)
Citrus sinensis
38. Find
the true match
Column
– I (Event) Column – II (Formation of )
I.
Apomixis A.
asexual embryos from nucellus
II.
Parthenogenesis B.
fruit from ovary without fertilisation
III.
Parthenocarpy C.
embryo from egg cell without fertilization
IV.
Polyembryony D.
Seeds from ovule without fertilization
I II III IV I II III IV
1) D C B A 2) C D A B
3) A B C D 4)
D C A B
39. Apomictic
seeds are found in
1) All flowering plants 2)
Allium and Cycas
3) All species of Asteraceae and
Grasses 4) Some
species of Asteraceae and Grasses
40. Select
the correct statements from the following
I)
Seeds of orange contain many embryos of different sizes and shapes
II)
Apomixis is a form of asexual reproduction that mimics sexual reproduction
III)
Double coconut is a worlds largest plant that gives rise to largest seeds
IV)
Dehydration and dormancy of mature seeds are crucial for storage of seeds for
future use
1)II&III 2)I II & IV 3)II & IV 4)I & IV
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