want to be a doctor?: CELL BIOLOGY UPTO CHROMOSOMES ASSIGNMENT

want to be a doctor?: CELL BIOLOGY UPTO CHROMOSOMES ASSIGNMENT

want to be a doctor?: NUCLEIC ACIDS AND CELL DIVISION

want to be a doctor?: NUCLEIC ACIDS AND CELL DIVISION

want to be a doctor?: TISSUES ASSIGNMENT

want to be a doctor?: TISSUES ASSIGNMENT

want to be a doctor?: INTERNAL ORGANISATION OF PLANTS-ASSIGNMENT

want to be a doctor?: INTERNAL ORGANISATION OF PLANTS-ASSIGNMENT

want to be a doctor?: PLANT ECOLOGY-ASSIGNMENT

want to be a doctor?: PLANT ECOLOGY-ASSIGNMENT

want to be a doctor?: GENETICS-ASSIGNMENT

want to be a doctor?: GENETICS-ASSIGNMENT

GENETICS-ASSIGNMENT

1	Among the following identify the Pea plant with only dominant characters. Inflated Yellow pods developed from axillary flowers Constricted green pods developed from terminal flowers Inflated yellow pods developed from terminal flowers Inflated green pods developed from axillary flowers Ans:Inflated green pods developed from axillary flowers
2	Arrange the following plants of Pea in a sequence of recessive to complete dominant features. I. Short plants with rounded seeds, green cotyledons and Grey testa II. Tall plants with wrinkled seeds, green cotyledons and Grey testa III. Yellow ripe pods, yellow cotyledons, round seeds and white testa IV. Green ripe pods with yellow cotyledons, round seeds developed on tall plats II, I, III, IV I, II, III, IV IV, III, II, I II, III, I, IV Ans:II, I, III, IV
3	Total number of Pea varieties collected by Mendel was 8 34 22 7 Ans:34
4	Mendel’s experimental results were not confirmed by Correns de Vriese Tschermak Boveri Ans:Boveri
5	The term Genetics was given by Mendel Sutton Correns Bateson Ans:Bateson
6	Choose the correct statements I. Mendel was the first to perform hybridization experiments II. Mendel was the first person to consider the results of hybridization in terms of single traits. III. Mendel counted and classified the progeny resulted from crosses in pea plants IV. Mendel compared the proportions of his hybridization results with mathematical models. all except I All All except I and II All except I and III Ans:all except I
7	[A]: Mendel identified Pea plants as suitable to carry out hybridization experiments [R]: Pisum sativum has bisexual flowers that naturally cross fertilised Both A and R are true and R is the correct explanation of A Both A and R are true but R is not the correct explanation of A A is true but R is false A is false but R is true Ans:A is true but R is false
8	Select the correct characters shown by Pisum sativum I. It is Annual II. It can be grown and handled easily III. It produces larger number of offspirings IV. It has well defined characters I and II II, III, IV I, II and III I, II, III, IV Ans:I, II, III, IV
9	Mendel’s experimental results were published as Laws of heredity Pisum – Plant hybridisation Experiments in Plant hybridisation Factors of Pea Ans:Experiments in Plant hybridisation
10	Choose the correct statements with respect to Monohybrid crosses I. Tall plants of parental generation do not have allele ‘t’. II. Tall plants of F1 generation do not have allele ‘t’. III. The plants of F2 generation without the allele ‘t’ and with only ‘t’ alleles exist in 1:1 ratio. IV. The ratio between the tall plants of F2 and F1 generation is 3:4. I, II, III II, III, IV I, III, IV I, II, IV Ans:I, III, IV
11	Individuals of the following genotypes are not seen in P and F1 generations during dihybrid cross Tt Rr TT RR TT rr tt rr Ans:TT rr
12	The assumptions made by Mendel through his experiments were sustained by the discovery of Chromosomal theory Cell lineage theory Meiosis Nucleosome theory Ans:Meiosis
13	Study the following table and choose the correct combination All except I All except III All except II All Ans:All except II
14	In Mendels dihybrid cross F2 individuals with the following genotype are formed in 1:1:1:1 ratio RR Yy, Rr YY, RR YY, rr yy RR YY, rr YY, RR Yy, rr yy rr yy, rr YY, RR YY, RR yy Rr Yy, RR Yy, rr YY, rr yy Ans:rr yy, rr YY, RR YY, RR yy
15	Arrange the following crosses in a sequence of gradual increase in the number of offspring with the genotype Rr Yy I. Rr YY X rR yY II. RR yy X rr YY III. Rr YY X Rr Yy IV. rr YY X RR Yy I, III, IV, II III, I, IV, II III, IV, I, II III, II, I, IV Ans:III, I, IV, II
16	In the following crosses all the individuals formed will be having similar genotype I. RR YY X rr yy II. rr YY X RR yy III. Rr YY X RR Yy IV. Rr Yy X RR YY I, III III, IV II, IV I, II Ans:I, II
17	Match the following A - II, B - III, C - IV, D - I A - III, B - II, C - I, D -IV A - II, B - V, C - IV, D - I A - III, B - V C - I, D -II Ans:A - II, B - V, C - IV, D - I
18	Plants with similar forms of alleles on homologous chromosomes are F1 hybrids of Monohybrid cross Dwarf pea plants Phenotypically tall pea plants Most of the F2 plants of dihybrid cross Ans:Dwarf pea plants
19	The ratio between the F2 plants of dihybrid cross with homologous and non-homologous alleles for both the traits is 1:1 1:4 1:2 1:8 Ans:1:1
20	When monohybrid crosses are made in Pea plants, the following fail to appear in F1 generation Plants with rounded seeds Plants with terminal flowers Plants with Inflated ripened pods Plants with Seeds having yellow cotyledons Ans:Plants with terminal flowers
21	[A]: All F1 plants of Monohybrid cross are tall [R]: F1 hybrids have the allele ‘t’. Both A and R are true and R is the correct explanation of A Both A and R are true but R is not the correct explanation of A A is true but R is false A is false but R is true Ans:Both A and R are true but R is not the correct explanation of A
22	Number of types of gametes formed by pea plant with genotype as AA, Tt, Yy, Rr is 4 6 16 8 Ans:8
23	Study the following with respect to Monohybrid cross and identify the suitable match A - V, B - IV, C - II D - I A - V, B - IV, C - II, D -III A - IV, B - V, C - I, D - II A - V, B- I, C - II, D - IV Ans:A - V, B - IV, C - II D - I
24	If a cross is made between between the pea plants with the genotypes as Rr Yy and rr Yy, the pea plants with the following genotypes can not be formed I. rr yy II. Rr YY III. RR yy IV. RR Yy I and III II and IV I and II III and IV Ans:III and IV
25	In a dihybrid cross, the ratio between the phenotypically similar individuals of F1 and F2 generations is 4:1 16:9 8:1 3:1 Ans:16:9
26	Match the following A - V, B - IV, C - II, D -I A - IV, B - V, C- I, D - III A - V, B - IV C - I, D - II A - V, B - I, C- II, D - IV Ans:A - V, B - IV, C - II, D -I
27	Out of 16 outcomes of an event , in how many out comes there is formation of Mendelian recombinants in F2 generation of Dihybrid cross. 10 4 3 6 Ans:6
28	Choose from the following where the probability is 1/4. I. Formation of gametes in F1 dihybrid with allele RY. II. Formation of dwarf plants in F2 generation of Mendelian Monohybrid cross. III. Formation of wrinkled seeds in F2 generation of Dihybrid cross. IV. Formation of Round green seeds in F2 generation of Dihybrid cross. All except I All except III All except IV All Ans:All except IV
29	2Arrange the following crosses with gradual increase in the probability of formation of Round and yellow seeded plants I. Ry Yy X rr yy II. rr Yy X RR yy III. RR Yy X RR Yy IV. Rr Yy X RR YY II, I, IV, III I, II, III, IV I, III, II, IV IV, III, II, I Ans:I, II, III, IV
30	Choose the set with mutually exclusive genotypic outcomes of an event for the formation of yellow seeds yy ; Yy ; yY YY ; yy YY ; Yy ; yY yy ; YY ; yY Ans:YY ; Yy ; yY
31	Choose the crosses that show the probability of formation of heterozygous Yellow seeded plants is 1/2. I. YY X Yy II. Yy X Yy III. yy X Yy I and II I and III II and III I, II, III Ans:I, II, III
32	The probability of formation of yellow round seeded plants in F2 generation of dihybrid cross which do not show the genotype Yy Ry is 3/16 9/16 5/16 1/16 Ans:5/16
33	By using the probability law, this is the correct explanation for the formation of F2 individuals of dihybrid cross with the genotype rr Yy 1/4 X 1/2 1/2 X 3/4 1/4 + 1/4 1/4 + 1/2 Ans:1/4 X 1/2
34	This is the correct explanation for the probability of obtaining F1 generation plants of Dihybrid cross with Yy Rr genotypes 1 X 1 1/2 X 1/2 1/4 + 1/4 1/2 + 1/2 Ans:1 X 1
35	Choose the genotypes of Mendel’s dihybrid cross whose probability in F2 generation is 1/2. Rr Yy RR Yy Ry yy None Ans:None
36	In a trihybrid cross, what is the probability of obtaining plants with the genotype RR Tt yy in F2 generation 1/4 x 1/2 X 1/2 1/4 x 1/2 x 1/4 1/2 x 1/2 + 1/4 1/2 x 1 x 1/2 Ans:1/4 x 1/2 x 1/4
37	Study the following table and choose the correct combinations with respect to Mendel’s dihybrid cross I and II I and III III and IV I and IV Ans:I and III
38	[A]: The probability of formation of F2 individuals of dihybrid cross with the genotype Rr YY is 1/8. [R]: The probability of formation of F2 individuals of Monohybrid cross with genotype Rr is 1/4 and with YY is 1/4. Both A and R are true and R is the correct explanation of A Both A and R are true but R is not the correct explanation of A A is true but R is false A is false but R is true Ans:A is true but R is false
39	When a heterozygous sweet pea plant with blue flowers and long pollen grains is test crossed , The progeny will not be having the following genotype RR r0r0 Rr R0r0 rr r0r0 Rr r0r0 Ans:RR r0r0
40	Chromosomal maps that show linked genes were prepared by Bateson Punnet T.H. Morgan Muller Ans:T.H. Morgan

PLANT ECOLOGY-ASSIGNMENT

1	Long and linear leaves are seen in Potamogeton Vallisneria Eichhornia Trapa Ans:Potamogeton
2	Eichhornia has i) Spongy stem ii) Spongy petiole iii) Balancing roots i is correct i and ii are correct i and iii are correct i, ii and iii are correct Ans:i, ii and iii are correct
3	Leaves of these hydrophytes are relatively larger Rooted hydrophytes with floating leaves Amphibious plants Free floating hydrophytes Submerged rooted hydrophytes Ans:Rooted hydrophytes with floating leaves
4	Assertion : Respirating roots of Jussiaea are adventitious. Reason : Hydrophytes usually have adventitious roots. Both A and R are true and R is the correct explanation of A Both A and R are true but R is not the correct explanation of A A is true but R is false A is false but R is true Ans:Both A and R are true and R is the correct explanation of A
5	Assimilatory epidermis is present in Vallisnaria Asparagus Zizyphus Calotropis Ans:Vallisnaria
6	Relatively wider cortex is seen in the roots of Asparagus Amnophila Aloe Acacia Ans:Asparagus
7	Sclerenchymatous hypodermis is seen in the leaves of Nerium Casuarina Pinus Ceiba Ans:Pinus
8	Identify the plant whose leaf is extended throughout the depth of waterbody Nelumbo Pistia Hydrilla Limnophila Ans:Nelumbo
9	Assertion : Sagittara has poorly developed xylem. Reason : Hydrophytes grow in water rich conditions. Both A and R are true and R is the correct explanation of A Both A and R are true but R is not the correct explanation of A A is true but R is false A is false but R is true Ans:Both A and R are true and R is the correct explanation of A
10	Assertion : Nymphaea is a hydrophyte. Reason : It has astrosclereids. Both A and R are true and R is the correct explanation of A Both A and R are true but R is not the correct explanation of A A is true but R is false A is false but R is true Ans:Both A and R are true but R is not the correct explanation of A
11	Study the following Identify the two correct items ii and iv iii and iv i and ii i and iii Ans:i and ii
12	Sub-aerial modified stems have no contact with the soil in Agave Nymphaea Eichhornia Hydrilla Ans:Eichhornia
13	Hydrochory is shown by Nelumbo Nymphaea Vallisneria Lemna Ans:Nymphaea
14	Sagittaria shows i) Heterophylly ii) Stoloniferous stem iii) Hydrophily i and ii ii and iii only i i and iii Ans:i and ii
15	Both aerial and underwater roots are seen in Pistia Victoria Jussiaea Ceratophyllum Ans:Jussiaea
16	Match the following and identify the correct match A. Plant having contact with only water I) Ranunculus B. Plant always having contact with both water and soil only II) Ceratophyllum C. Plant always having contact with air and water III) Cyperus D. Plant always having contact with air water and soil IV) Salvinia V) Potamogeton A-II, B-V, C-IV, D-I A-II, B-V, C-III, D-I A-II, B-IV, C-I, D-V A-V, B-II, C-IV, D-III Ans:A-II, B-V, C-IV, D-I
17	The following plant has relatively more developed xylem Trapa Typha Wolffia Utricularia Ans:Typha
18	The hydrophyte with developed root caps is Azolla Lemna Hydrilla Cyperus Ans:Cyperus
19	All leaves of the plant are dissected and root like in Limnophila Sagittaria Vallisneria Ceratophyllum Ans:Ceratophyllum
20	Odum defined ecology as Study of organisms with respect to environment Study of ecosystems Study of reciprocal relationships between plants and animals Study of various species of plants Ans:Study of ecosystems
21	This plant has contact with neither atmosphere nor soil Salvinia Utricularia Typha Trapa Ans:Utricularia
22	Assertion : Pistia has root pocket. Reason : All hydrophytes lack root caps. Both A and R are true and R is the correct explanation of A Both A and R are true but R is not the correct explanation of A A is true but R is false A is false but R is true Ans:A is true but R is false
23	Choose the correct statement All hydrophytes have root system All hydrophytes lack root caps All hydrophytes lack cuticle All hydrophytes have aerenchyma Ans:All hydrophytes have aerenchyma
24	Study the following Identify the two correct items i and ii ii and iii iii and iv ii and iv Ans:iii and iv
25	This hydrophyte can effectively survive for some time in dry period Pistia Hydrilla Cyperus Lemna Ans:Cyperus
26	Match the following A. Hydrilla I) Bulbs B. Nymphaea II) Rhizome C. Aloe III) Bulbils D. Agave IV) Fragmentation V) Suckers A - IV, B - II, C - V, D - I A - IV, B - II, C - V, D - III A - II, B - IV, C - V, D - III A - II, B - III, C - IV, D - V Ans:A - IV, B - II, C - V, D - III
27	Stem doesn’t store water in Opuntia Euphorbia Bulbophyllum Casuarina Ans:Casuarina
28	Arrange the following hydrophytic plants in a sequence of plants ‘having contact with soil and water’, ‘with only water’, ‘with water and atmosphere’ and ‘with water’ and ‘soil and atmosphere’ i) Ceratophyllum ii) Sagittaria iii) Eichhornia iv) Potamogeton iv, i, iii, ii iv, iii, i, ii i, iv, iii, ii iv, i, ii, iii Ans:iv, i, iii, ii
29	Assertion : Tribulus usually grows in Arid zones. Reason : Xerophytes can grow only in water scarcity conditions. Both A and R are true and R is the correct explanation of A Both A and R are true but R is not the correct explanation of A A is true but R is false A is false but R is true Ans:A is true but R is false
30	Assertion : Well developed root cap is seen in Cyperus. Reason : It is an amphibious plant. Both A and R are true and R is the correct explanation of A Both A and R are true but R is not the correct explanation of A A is true but R is false A is false but R is true Ans:Both A and R are true and R is the correct explanation of A
31	Leaves of Potamogeton are Ribbon shaped Needle like Linear Lanceolate Ans:Linear
32	Match the following A. Rootless hydrophyte I) Cyperus B. Hydrophyte with horizontally growing stem II) Nelumbo C. Epistomatous plant III) Ranunculus D. Hydrophyte surviving in dry periods IV) Wolffia V) Azolla A - IV, B - V, C - II, D - III A - IV, B - V, C - II, D - I A - V, B - IV, C - I, D - II A - IV, B - III, C - I, D - II Ans:A - IV, B - V, C - II, D - I
33	Assertion : Eichhornia root shows polyarch and exarch condition. Reason : It is a hydrophyte. Both A and R are true and R is the correct explanation of A Both A and R are true but R is not the correct explanation of A A is true but R is false A is false but R is true Ans:Both A and R are true but R is not the correct explanation of A
34	Succulent xerophyte with epidermal cells storing water is Aloe Bryophyllum Peperomia Opuntia Ans:Peperomia
35	Leaves are not transluscent in Vallisneria Hydrilla Pistia Potamogeton Ans:Pistia
36	Study the following Identify the two correct items i and ii i and iv iii and iv ii and iii Ans:i and iv
37	Hydrophyte with some aerial and with some underwater leaves Eichhornia Potamogeton Vallisneria Salvinia Ans:Salvinia
38	Assertion : Tribulus shows mesophytic characters. Reason : It never faces water deficient conditions. Both A and R are true and R is the correct explanation of A Both A and R are true but R is not the correct explanation of A A is true but R is false A is false but R is true Ans:Both A and R are true and R is the correct explanation of A
39	Match the following and identify the correct match A. Leaves with multilayered sclerenchymatous hypodermis I)Tribulus B. Leaves with multiple epidermis II)Aloe C. Stems with multilayered sclerenchymatous hypodermis III)Nerium D. Leaves with mucilaginous mesophyll IV)Pinus V)Casuarina A-V, B-IV, C-II, D-I A-IV, B-V, C-I, D-II A-IV, B-III, C-V, D-II A-IV, B-III, C-II, D-I Ans:A-IV, B-III, C-V, D-II