| 1 | Among the following identify the Pea plant with only dominant characters. Ans:Inflated green pods developed from axillary flowers |
| 2 | Arrange the following plants of Pea in a sequence of recessive to complete dominant features. I. Short plants with rounded seeds, green cotyledons and Grey testa II. Tall plants with wrinkled seeds, green cotyledons and Grey testa III. Yellow ripe pods, yellow cotyledons, round seeds and white testa IV. Green ripe pods with yellow cotyledons, round seeds developed on tall plats Ans:II, I, III, IV |
| 3 | Total number of Pea varieties collected by Mendel was Ans:34 |
| 4 | Mendel’s experimental results were not confirmed by Ans:Boveri |
| 5 | The term Genetics was given by Ans:Bateson |
| 6 | Choose the correct statements I. Mendel was the first to perform hybridization experiments II. Mendel was the first person to consider the results of hybridization in terms of single traits. III. Mendel counted and classified the progeny resulted from crosses in pea plants IV. Mendel compared the proportions of his hybridization results with mathematical models. Ans:all except I |
| 7 | [A]: Mendel identified Pea plants as suitable to carry out hybridization experiments [R]: Pisum sativum has bisexual flowers that naturally cross fertilised Ans:A is true but R is false |
| 8 | Select the correct characters shown by Pisum sativum I. It is Annual II. It can be grown and handled easily III. It produces larger number of offspirings IV. It has well defined characters Ans:I, II, III, IV |
| 9 | Mendel’s experimental results were published as Ans:Experiments in Plant hybridisation |
| 10 | Choose the correct statements with respect to Monohybrid crosses I. Tall plants of parental generation do not have allele ‘t’. II. Tall plants of F1 generation do not have allele ‘t’. III. The plants of F2 generation without the allele ‘t’ and with only ‘t’ alleles exist in 1:1 ratio. IV. The ratio between the tall plants of F2 and F1 generation is 3:4. Ans:I, III, IV |
| 11 | Individuals of the following genotypes are not seen in P and F1 generations during dihybrid cross Ans:TT rr |
| 12 | The assumptions made by Mendel through his experiments were sustained by the discovery of Ans:Meiosis |
| 13 | Study the following table and choose the correct combination Ans:All except II |
| 14 | In Mendels dihybrid cross F2 individuals with the following genotype are formed in 1:1:1:1 ratio Ans:rr yy, rr YY, RR YY, RR yy |
| 15 | Arrange the following crosses in a sequence of gradual increase in the number of offspring with the genotype Rr Yy I. Rr YY X rR yY II. RR yy X rr YY III. Rr YY X Rr Yy IV. rr YY X RR Yy Ans:III, I, IV, II |
| 16 | In the following crosses all the individuals formed will be having similar genotype I. RR YY X rr yy II. rr YY X RR yy III. Rr YY X RR Yy IV. Rr Yy X RR YY Ans:I, II |
| 17 | Match the following Ans:A - II, B - V, C - IV, D - I |
| 18 | Plants with similar forms of alleles on homologous chromosomes are Ans:Dwarf pea plants |
| 19 | The ratio between the F2 plants of dihybrid cross with homologous and non-homologous alleles for both the traits is Ans:1:1 |
| 20 | When monohybrid crosses are made in Pea plants, the following fail to appear in F1 generation Ans:Plants with terminal flowers |
| 21 | [A]: All F1 plants of Monohybrid cross are tall [R]: F1 hybrids have the allele ‘t’. Ans:Both A and R are true but R is not the correct explanation of A |
| 22 | Number of types of gametes formed by pea plant with genotype as AA, Tt, Yy, Rr is Ans:8 |
| 23 | Study the following with respect to Monohybrid cross and identify the suitable match Ans:A - V, B - IV, C - II D - I |
| 24 | If a cross is made between between the pea plants with the genotypes as Rr Yy and rr Yy, the pea plants with the following genotypes can not be formed I. rr yy II. Rr YY III. RR yy IV. RR Yy Ans:III and IV |
| 25 | In a dihybrid cross, the ratio between the phenotypically similar individuals of F1 and F2 generations is Ans:16:9 |
| 26 | Match the following Ans:A - V, B - IV, C - II, D -I |
| 27 | Out of 16 outcomes of an event , in how many out comes there is formation of Mendelian recombinants in F2 generation of Dihybrid cross. Ans:6 |
| 28 | Choose from the following where the probability is 1/4. I. Formation of gametes in F1 dihybrid with allele RY. II. Formation of dwarf plants in F2 generation of Mendelian Monohybrid cross. III. Formation of wrinkled seeds in F2 generation of Dihybrid cross. IV. Formation of Round green seeds in F2 generation of Dihybrid cross. Ans:All except IV |
| 29 | 2Arrange the following crosses with gradual increase in the probability of formation of Round and yellow seeded plants I. Ry Yy X rr yy II. rr Yy X RR yy III. RR Yy X RR Yy IV. Rr Yy X RR YY Ans:I, II, III, IV |
| 30 | Choose the set with mutually exclusive genotypic outcomes of an event for the formation of yellow seeds Ans:YY ; Yy ; yY |
| 31 | Choose the crosses that show the probability of formation of heterozygous Yellow seeded plants is 1/2. I. YY X Yy II. Yy X Yy III. yy X Yy Ans:I, II, III |
| 32 | The probability of formation of yellow round seeded plants in F2 generation of dihybrid cross which do not show the genotype Yy Ry is Ans:5/16 |
| 33 | By using the probability law, this is the correct explanation for the formation of F2 individuals of dihybrid cross with the genotype rr Yy Ans:1/4 X 1/2 |
| 34 | This is the correct explanation for the probability of obtaining F1 generation plants of Dihybrid cross with Yy Rr genotypes Ans:1 X 1 |
| 35 | Choose the genotypes of Mendel’s dihybrid cross whose probability in F2 generation is 1/2. Ans:None |
| 36 | In a trihybrid cross, what is the probability of obtaining plants with the genotype RR Tt yy in F2 generation Ans:1/4 x 1/2 x 1/4 |
| 37 | Study the following table and choose the correct combinations with respect to Mendel’s dihybrid cross Ans:I and III |
| 38 | [A]: The probability of formation of F2 individuals of dihybrid cross with the genotype Rr YY is 1/8. [R]: The probability of formation of F2 individuals of Monohybrid cross with genotype Rr is 1/4 and with YY is 1/4. Ans:A is true but R is false |
| 39 | When a heterozygous sweet pea plant with blue flowers and long pollen grains is test crossed , The progeny will not be having the following genotype Ans:RR r0r0 |
| 40 | Chromosomal maps that show linked genes were prepared by Ans:T.H. Morgan |
ASTHRA
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Tuesday, March 13, 2012
GENETICS-ASSIGNMENT
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